32y^6+4y^2=

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Solution for 32y^6+4y^2= equation: 


Simplifying
32y6 + 4y2 = 0

Reorder the terms:
4y2 + 32y6 = 0

Solving
4y2 + 32y6 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '4y2'.
4y2(1 + 8y4) = 0

Ignore the factor 4.

Subproblem 1
Set the factor 'y2' equal to zero and attempt to solve:

Simplifying
y2 = 0

Solving
y2 = 0

Move all terms containing y to the left, all other terms to the right.

Simplifying
y2 = 0

Take the square root of each side:
y = {0}

Subproblem 2
Set the factor '(1 + 8y4)' equal to zero and attempt to solve:

Simplifying
1 + 8y4 = 0

Solving
1 + 8y4 = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 8y4 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 8y4 = 0 + -1
8y4 = 0 + -1

Combine like terms: 0 + -1 = -1
8y4 = -1

Divide each side by '8'.
y4 = -0.125

Simplifying
y4 = -0.125

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
y = {0}

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